Question

find hcf of 25,40,120 by prime factorisation method​

Answer 1

Answer:

25/5 =5

40/2=20

20/2=10

10/2=5

120/2=60

60/2=30

30/2= 15

15/3= 5

5 is the common in 25 ,40 ,120 .5×5×5 =125

125 is HCF of 25, 40, 120 .

Answer 2

Answer:

$25 = 5 \times 5 \\ 40 = 2 \times 2 \times 2 \times 5 \\ 120 = 2 \times 2\times 2 \times 5 \times 3 \\ so \\ \: hcf = 5$