Question

find HCF of 2ab^3+2ab^2+2abc^2, b^3c+b^4,b^4+b^2c^2+c^4

Answer 1

Answer:

1

Step-by-step explanation:

2abbb + 2abb + 2abcc = 2ab(bb+b+cc)

bbbc + bbbb= bbb(c+b)

bbbb + bbcc+ cccc = 1(bbbb+bbcc+cccc)

if you are asking about hcf for every term before comma, then above answer outside the brackets is valid

2ab

bbb

1

if you are asking about hcf for all the above terms combined , then it is 1.