find hcf of 4052 and 420 by prime factorisation method and sent answe by step by step
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Answer:
4
Step-by-step explanation:
Let us represent 4052 and 420 as a product of its prime factors.
Prime factorization of 4052 is 2 × 2 × 1013
Prime factorization of 420 is 2 × 2 × 3 × 5 × 7
The common prime factors are 2 and 2
HCF is the product of the prime factors that are common to each of the given numbers.
HCF of 4052 and 420 is 4
There the HCF of 4052 and 420 is 4
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