Math, asked by gautam152007, 1 month ago

find hcf of 4052 and 420 by prime factorisation method and sent answe by step by step​

Answers

Answered by vanshikaa70
0

Answer:

4

Step-by-step explanation:

Let us represent 4052 and 420 as a product of its prime factors.

Prime factorization of 4052 is 2 × 2 × 1013

Prime factorization of 420 is 2 × 2 × 3 × 5 × 7

The common prime factors are 2 and 2

HCF is the product of the prime factors that are common to each of the given numbers.

HCF of 4052 and 420 is 4

There the HCF of 4052 and 420 is 4

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