find HCF of 615 and 154 using Euclid's division
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Answer:
Step-by-step explanation:
by euclid's division lemma,
a = bq +r [r<=0]
615 = 154 *3 + 153
154 = 153 *1 + 1
153 = 1 * 153 + 0
∴ HCF [615,153] = 1
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