find HCF of 65 and 117 and Express it in the form of 65 M + 117 m
Answers
Answered by
21
Hiii friend,
Prime factorisation of 65 = 5 × 13
Prime factorisation of 117 = 3 × 3 × 13
HCF of 65 and 117 = 13
According to question,
65M+117M = 13
182M = 13
M = 13/182 => 1/14.
HOPE IT WILL HELP YOU..... :-)
Prime factorisation of 65 = 5 × 13
Prime factorisation of 117 = 3 × 3 × 13
HCF of 65 and 117 = 13
According to question,
65M+117M = 13
182M = 13
M = 13/182 => 1/14.
HOPE IT WILL HELP YOU..... :-)
sunnu129:
yaa u helped mee
Answered by
22
Hey, here
Sol.
Since 117 > 65
Division lemme of 117 > 65 :
=> 117 = 65 × 1 + 52
=> 65 = 52 × 1 + 13
=> 52= 4 × 13 + 0
In this step the remainder is zero.
Thus, the division 13 in this step in the HCF of the given number
The HCF of 65 and 117 is 13
Now,
THEREFORE HCF of 65 and 117 is in the form 65m + 117 m , where
m=2 and m= -1
_____________________________
Hope it's helps you
☺☺
Sol.
Since 117 > 65
Division lemme of 117 > 65 :
=> 117 = 65 × 1 + 52
=> 65 = 52 × 1 + 13
=> 52= 4 × 13 + 0
In this step the remainder is zero.
Thus, the division 13 in this step in the HCF of the given number
The HCF of 65 and 117 is 13
Now,
THEREFORE HCF of 65 and 117 is in the form 65m + 117 m , where
m=2 and m= -1
_____________________________
Hope it's helps you
☺☺
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