Find hcf of 81 and 237 and express it in linear combination...plz urgent
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237=81*2+75..........(1)
81=75*1+6.........(2)
75=6*12+3..........(3)
6=3*2+0.........(4)
so the HCF of 81 and 237 will be 3. now to expresss it as a linear combination of 81 and 237 . from(3)we have , 3=75-6*12 =>3=75-(81-75*1)*12 =>3=13*75-12*81 =>3=13*(237-81*2)-12*81 =>3=13*237-26*81-12*81 =>3=13*237-38*81 =>3=237x+81y,
where x=130 and y=-38.
Hope this helps.
ask me if you need anymore help
81=75*1+6.........(2)
75=6*12+3..........(3)
6=3*2+0.........(4)
so the HCF of 81 and 237 will be 3. now to expresss it as a linear combination of 81 and 237 . from(3)we have , 3=75-6*12 =>3=75-(81-75*1)*12 =>3=13*75-12*81 =>3=13*(237-81*2)-12*81 =>3=13*237-26*81-12*81 =>3=13*237-38*81 =>3=237x+81y,
where x=130 and y=-38.
Hope this helps.
ask me if you need anymore help
jojov:
Please mark this as the brainliest
:))
Ya got it THANKS AAA LLOOTT YRR
Thank u thank u thank u
:))))
Its no problem haha
any simpler method??
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