Find HCF of 90 and 126 by Euclid's division algorithm also find LCM and verify that LCM×HCF = product of two numbers
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Answered by
41
here,
126> 90
so by Euclid division lemma
126 = 90 ×1 + 36
90= 36× 2 + 18
36 = 18 × 2 +0
therefore HCF( 90,126) = 18
and LCM (90,126) =630
verification:-
LCM ×HCF =product of two no.
Taking LHS
LCM × HCF = 18× 630 = 11340
Taking RHS
product of two no. = 90 × 126= 11340
LHS = RHS
hence verified
126> 90
so by Euclid division lemma
126 = 90 ×1 + 36
90= 36× 2 + 18
36 = 18 × 2 +0
therefore HCF( 90,126) = 18
and LCM (90,126) =630
verification:-
LCM ×HCF =product of two no.
Taking LHS
LCM × HCF = 18× 630 = 11340
Taking RHS
product of two no. = 90 × 126= 11340
LHS = RHS
hence verified
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1
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