Find HCF of following pairs :-
1200 and 28
Answers
Answered by
1
Answer:
4
Step-by-step explanation:
1200= 2x2x2x2x3x5x5
28=2x2x7
HCF= 2x2 =4
Answered by
0
Answer:
4
Step-by-step explanation:
1. Write each number as a product of their prime factors
1200 = 2 x 2 x 2 x 2 x 3 x 5 x 5
28 = 2 x 2 x 7
2. Draw a venn diagram
One circle for 1200, and one for 28. Fill in the venn diagram using the numbers above e.g. 2 would go in the middle as it is in both numbers. You would have another 2 in the middle as well because it is repeated again.
3. Multiply the numbers in the middle together
Once you have filled in your venn diagram, multiply the numbers in the middle together. If you were trying to find the LCM you would multiply all the numbers in the venn diagram together.
Similar questions