Find hcf of numbers 134791, 6341 and 6339 by euclid's division algorithm.
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We know that,
a = bq + r, where 0 ≤ r <b.
According to the question apply the division lemma to 6339 & 6341.
➡ 6341 = 6339 * 1 + 2
➡6339 = 2 * 3169 + 1
➡ 2 = 2 * 1 + 0
➡ The remainder is zero.
➡ so HCF ( 6341, 6339 ) = 1
Now, we have to find the HCF of 1 & 134791.
➡ 134791 = 1 * 134791 + 0
➡ Now, HCF ( 1, 134791 ) = 1
Therefore HCF ( 6339, 6341, 134791 ) = 1
Hope it will help you !!!
a = bq + r, where 0 ≤ r <b.
According to the question apply the division lemma to 6339 & 6341.
➡ 6341 = 6339 * 1 + 2
➡6339 = 2 * 3169 + 1
➡ 2 = 2 * 1 + 0
➡ The remainder is zero.
➡ so HCF ( 6341, 6339 ) = 1
Now, we have to find the HCF of 1 & 134791.
➡ 134791 = 1 * 134791 + 0
➡ Now, HCF ( 1, 134791 ) = 1
Therefore HCF ( 6339, 6341, 134791 ) = 1
Hope it will help you !!!
Answered by
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