find HCF of the following by Euclid division algorithm 592 and 252
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12
Euclid division algorithm
592=252×2+88
252=88×2+76
88=76×1+12
76=12×6+4
12=4×3+0
Hence,the HCF is 4
Hope it helps
Answered by
4
Answer:
592=252*2 +88
252=88*2+76
88=76*1+12
76=12*6+4
12=4*3+0
HCF = 4
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