Find HCF of (x+1)(x²-4) and(x²-1)(x-2) is
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Answer:
(x+1)
Step-by-step explanation:
(x+1)(x.x-4) here x.x -4 or x.x -2.2 is in the form of a.a-b.b
=(x+1)(x+2)(x-2)
(x.x-1)(x-2)
=(x.x-1.1)(x-2) here x.x-1.1 is also is in the firm of a.a-b.b
=(x+1)(x-1)(x-2)
So,here the common factors are (x+1)&(x-2)
So, the hcf is (x+1).
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