Find hcf of X cube - 3x + 2
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Answer :
Your question needs some correction.
It should be -
"Factorize (x³ - 3x + 2)"
Now, x³ - 3x + 2
= x³ - 1 - 3x + 3
= (x³ - 1) - 3 (x - 1)
= (x - 1) (x² + x + 1) - 3 (x - 1)
= (x - 1) (x² + x + 1 - 3)
= (x - 1) (x² + x - 2)
= (x - 1) (x² + 2x - x - 2)
= (x - 1) {x (x + 2) - 1 (x + 2)}
= (x - 1) (x + 2) (x - 1),
which is the required factorization.
#MarkAsBrainliest
Your question needs some correction.
It should be -
"Factorize (x³ - 3x + 2)"
Now, x³ - 3x + 2
= x³ - 1 - 3x + 3
= (x³ - 1) - 3 (x - 1)
= (x - 1) (x² + x + 1) - 3 (x - 1)
= (x - 1) (x² + x + 1 - 3)
= (x - 1) (x² + x - 2)
= (x - 1) (x² + 2x - x - 2)
= (x - 1) {x (x + 2) - 1 (x + 2)}
= (x - 1) (x + 2) (x - 1),
which is the required factorization.
#MarkAsBrainliest
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