Question

Find he component of veca=2hati+3hatj along the direction of vectors (hati+hatj)

Answer 1

Answer:

Explanation:

Aloha !

Let a= 2î+3j

Now along b= î+j

So that,

(2î+3j)(î+j)/√2

=5/√2×(î+j)/√2

Thank you

@ Twilight Astro ✌️☺️❤️

Answer 2

Answer:

$\large{\boxed{\green{\mathcal{Answer-}}}}$

let a = 2î+ 3j

now along b = î + j

so that ;

(2î + 3j) (î + j) / root 2

= 5 / root 2 + (î + j ) / root 2

HOPE THAT HELPS