find heat lost by copper cube of mass of 400g when it cools from 100°c to 30°C specific heat of copper is equal to 390 j/kg°C
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Explanation:
m=400g=0.4kg
C=390Jkg−1oC−1
T1=100oC,T2=30oC
ΔT=70oC
∴ Heat lost =mC(T1−T2)
=0.4×390×70J=
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