Question

find height of a triangle whose area is 20 square metreand base in 10m is​

Answer 1

Answer:

b=20cm ; h=10cm

A=2hb=210×20

=2200

= 100cm2



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Answer 2

Explanation:

Question :-

• Find the height of a triangle whose area is 20 m² and base is 10 m.

To Find :-

• Height of triangle.

Solution :-

Given :

• Area = 20 m²
• Base = 10 m

By using the formula,

${\sf{\longrightarrow Area\ of\ triangle\ =\ \dfrac{1}{2} \times b \times h}}$

Where,

• b = base
• h = height

According to the question, by using the formula, we get :

${\sf{\longrightarrow Area\ of\ triangle\ =\ \dfrac{1}{2} \times b \times h}}$

${\sf{\longrightarrow 20\ =\ \dfrac{1}{\cancel2} \times \cancel{10} \times h}}$

${\sf{\longrightarrow 20\ =\ 5h}}$

${\sf{\longrightarrow \dfrac{20}{5}\ =\ h}}$

${\sf{\longrightarrow 4\ =\ h}}$

${\sf{\longrightarrow h\ =\ 4\ m}}$

$\therefore$ Hence, height of triangle is 4 m.

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$