Math, asked by preetimathur3714, 3 months ago

Find the derivative of x²/³ (3x²-2x+5).

Answers

Answered by gyaneshwarsingh882
0

Answer:

Step-by-step explanation:

d/dx {x²/³ (3x²-2x+5)}

= d/dx{(x^2/3)} . (3x²-2x+5) + x^2/3 . d/dx(3x²-2x+5)

= 2/3.x^(2/3-1) . (3x²-2x+5) + x^2/3 . (6x - 2 + 0)

= 2/3. x^(-1/3) . (3x²-2x+5) + x^2/3 . (6x - 2)

= 2/3 . 1/(x^1/3) . (3x²-2x+5) + x^2/3 . (6x - 2) (ans.)

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