find highest common factor(HCF) of 231, 396 is
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Using Euclid's Division Lemma,
396 = 231*1 + 165,
=> 231 = 165*1 + 66,
=> 165 = 66*2 + 33,
=> 66 = 33*2 + 0,
Here using 33 we got the remainder 0, So the greatest H.C.F must be 33,
Euclid's Division Lemma States that, If there are a and b numbers with a>b, Then there exists a relation such as
a = bq + r, Where range of r is from 0 to b, and can equal to 0, and q is some integer !
So therefore the answer is 33,
Hope you understand, Have a Great Day, Merry Christmas !
Thanking you, Bunti 360 !
396 = 231*1 + 165,
=> 231 = 165*1 + 66,
=> 165 = 66*2 + 33,
=> 66 = 33*2 + 0,
Here using 33 we got the remainder 0, So the greatest H.C.F must be 33,
Euclid's Division Lemma States that, If there are a and b numbers with a>b, Then there exists a relation such as
a = bq + r, Where range of r is from 0 to b, and can equal to 0, and q is some integer !
So therefore the answer is 33,
Hope you understand, Have a Great Day, Merry Christmas !
Thanking you, Bunti 360 !
charry3:
marry christmas
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