Math, asked by khanwaleed098, 1 month ago

Find how many five-digit numbers can be made using the digits 2, 3, 4, 5 and 6 once each if:

a there are no restrictions

b the five-digit number must be:

i odd ii even iii odd and less than 40000.​

Answers

Answered by mbakshi37
2

Answer:

120 , 72 , 48 , 48

Step-by-step explanation:

a. 5x4x3x2x1= 120

b. i 3/5 of 120 = 360/5 = 72

ii 2/5 of 120 =:48

iii 2/5 of 120 =48

Answered by ayanashami
0

Answer:

120

48

72

18

Step-by-step explanation:

a. 5! = 120 ways
b.

i. 4!*4! = 48 ways
ii. 4!*4! *4! = 72 ways

iii. 3!*3 = 18 ways

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