Question

Find how much more is 15a²b²+12b²c-4c²a+11a²b than 12a²b²-12c²a+22a²b-3b²c.
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Answer 1

Answer:

Answer is =3a²b²+15b²c+8c²a-11a²b

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Answer 2

$</p><p>generally \: question \\ \\ 15a²b²+12 b²c-4c²a+11a²b \: \\ than \: \\ 12a²b²-12c²a+22a²b-3b²c. \\ \\ ans. \: \: (15a²b²+12b²c-4c²a+11a²b) - \\ ( 12a²b²-12c²a+22a²b-3b²c) \\ \\ = (15a²b² - 12a²b²)-( + 12b²c + 3b²c) \\ ( - 4c²a + 12c²a) +( 11a²b - 22a²b) \\ \\ = 3a²b²+15b²c+8c²a-11a²b \: \: \:$