Question

Find hypotenuse & perimeter of Δ ABC, where AB = 2 cm & BC = 3 cm.​

Answer 1

Answer:

i hope it will help u.....

Answer 2

Question:-

Find hypotenuse & perimeter of Δ ABC, where AB = 2 cm & BC = 3 cm.

Solution:-

We use Pythagoras theorem

=> ( AC )² = ( AB )² + ( BC )²

=> ( AC )² = ( 2 )² + ( 3 )²

=> ( AC )² = 4 + 9

=> ( AC)² = 13

=> AC = √13 cm

=>Perimeter of Δ ABC = AB+BC+AC

=>Perimeter of Δ ABC = 2+3+√5

=>Perimeter of Δ ABC = 5+√13 cm

Hence Hypotenuse & Perimeter are

√13 cm & 5+√13cm respectively.

i hope it helps you.