Question

simplify(p-2)(p+1)(p-4)​

Answer 1

Answer:

Step-by-step explanation:

(p-2) (p-1) (p-4)

(p*p+p*-1-2*p-2*-1) (p-4)

(P^2-p-2p+2)(p-4)

(p^2-3p+2)(p-4)

(p^2*p+p^2*-4-3p*p-3p*-4+2*p+2*-4)

(p^3-4p^2-3p^2+12p+2p-8)

(p^3-7p^2+14p-8)

Answer 2

Answer:

p^2+7p+14p+8

Step-by-step explanation:

comparing (p-2)(p+1)(p-4) with (x+a)(x+b)(x+c) we get:-

a=2,b=1,c=4

______________________________________

(x+a)(x+b)(x+c)=x^2+ (a+b+c)x + (ab+bc+ca)x+ABC | ______________________________________|

(p-2)(p+1)(p-4)= p^2+(2+1+4)p+{(2)(1)+(1)(4)+(4)(2)}p+(2)(1)(4)

=p^2+7p+(2+4+8)p+8

=p^2+7p+(6+8)p+8

=p^2+7p+14p+8//

hope it is helpful.

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