Question

find impulse I
if mass= 30 kg
velocity i = 20 m/s
time=5sec
force =30N
​

Answer 1

Answer:

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v=u+at

a=

t

(v−u)

=

25

(3.5−2)

=0.06m/s

2

As per Newton's second law of motion, force is given as:

F=ma

=3×0.06=0.18N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion

Answer 2

Explanation:

Mass of the body, m = 3 kg

Mass of the body, m = 3 kgInitial speed of the body, u = 2 m/s

Mass of the body, m = 3 kgInitial speed of the body, u = 2 m/sFinal speed of the body, v = 3.5 m/s

Mass of the body, m = 3 kgInitial speed of the body, u = 2 m/sFinal speed of the body, v = 3.5 m/sTime, t = 25 s

Mass of the body, m = 3 kgInitial speed of the body, u = 2 m/sFinal speed of the body, v = 3.5 m/sTime, t = 25 sUsing the first equation of motion, the acceleration (a) produced in the body can be calculated as:

Mass of the body, m = 3 kgInitial speed of the body, u = 2 m/sFinal speed of the body, v = 3.5 m/sTime, t = 25 sUsing the first equation of motion, the acceleration (a) produced in the body can be calculated as:v=u+at

Mass of the body, m = 3 kgInitial speed of the body, u = 2 m/sFinal speed of the body, v = 3.5 m/sTime, t = 25 sUsing the first equation of motion, the acceleration (a) produced in the body can be calculated as:v=u+ata=t(v−u)

Mass of the body, m = 3 kgInitial speed of the body, u = 2 m/sFinal speed of the body, v = 3.5 m/sTime, t = 25 sUsing the first equation of motion, the acceleration (a) produced in the body can be calculated as:v=u+ata=t(v−u)   =25(3.5−2)=0.06m/s2