Question

if the zeros of the polynomial x3-3x^2+x+1 are (a-b), a, (a+b), find a and b​

Answer 1

Answer:

A=1 b= plus minus 2

Step-by-step explanation:

a−b,a,a+b are zeroes of x3−3x2+x+1

⇒a−b+a+a+b= sum of zeroes = 3

⇒3a=3

⇒a=1

(a−b)(a)(a+b)= product of zeroes =−1

⇒(1−b)(1+b)=−1

⇒1−b2=−1

⇒b2=2

⇒b=±2

Answer 2

Answer:

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