Find increase in tension in the wire electrostatic
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hi
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In the first, the approximate formula for the capacitance of a ring is:
C=πRln(8Rr)(CGS−system)C=πRln(8Rr)(CGS−system)
where R is a radius of the ring and r is a radius of the wire. (R>>rR>>r)
Let qq be the total charge(distributed uniformly) of the ring. Then the electrostatic energy of the ring:
Wq=q22CWq=q22C
Now, the radial force (due to the electrostatic repulsions), applied to the ring, can be obtained from a simple differentiation:
FR=−dWqdRFR=−dWqdR
Thus
FR=q22πln(8Rr)R2FR=q22πln(8Rr)R2
The tension TT in the wire:
T=FR2π=(
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