Find integers x and y where
√3 / (2√3 + 3) = (x + y√3)
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√3 = √3 (2√3 - 3) = 6 - 3√3 = 2 - √3
2√3 + 3 (2√3 + 3) (2√3 - 3) 12 - 9
x = 2
y = -1
annamsen:
From 2 - sqrt(3) = x + y sqrt(3) one can infer the answer as x = 2 and
y = -1. However, this is also a condition of 1 equation with 2 unknowns. Is there another trick to solving this?
perhaps by graphing?
it is correct
we got an answer 2 - √3 ie 2 + (-√3) = In question it is given x + y√3 Here y√3 = 1√3 so other number is x of course.
y = -1 and x = 2
Thank you!
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