Question

Find Integral of:

Plz solve it . Dont give the answer only

Answer 1

Hope ur answer is cleared. And if u r satisfied with the answer mark me as brainliest.

Answer 2

$\int ( 6 x + 5 x ^ { 2 } - 2 x ^ { 3 } + \frac { 1 } { x ^ { 2 } } ) d x \\ \\ \int 6x\mathrm{d}x+\int 5x^{2}\mathrm{d}x+\int -2x^{3}\mathrm{d}x+\int \frac{1}{x^{2}}\mathrm{d}x \\ \\ 6\int x\mathrm{d}x+5\int x^{2}\mathrm{d}x-2\int x^{3}\mathrm{d}x+\int \frac{1}{x^{2}}\mathrm{d}x \\ \\ 3x^{2}+5\int x^{2}\mathrm{d}x-2\int x^{3}\mathrm{d}x+\int \frac{1}{x^{2}}\mathrm{d}x \\ \\ 3x^{2}+\frac{5x^{3}}{3}-2\int x^{3}\mathrm{d}x+\int \frac{1}{x^{2}}\mathrm{d}x \\ \\ 3x^{2}+\frac{5x^{3}}{3}-\frac{x^{4}}{2}+\int \frac{1}{x^{2}}\mathrm{d}x \\ \\ 3x^{2}+\frac{5x^{3}}{3}-\frac{x^{4}}{2}-\frac{1}{x} \\ \\ 3x^{2}+\frac{5x^{3}}{3}-\frac{x^{4}}{2}-\frac{1}{x}+С$

$\huge \ \mathfrak{@DarkShadow7083 }$