Question

find integral zeros of the polynomial (x+3) (x-7)

Answer 1

Given:

(x+3) (x-7)

To find:

The integral zeros of the given polynomial.

Solution:

1) Polynomial is the expression of the sum of variables with different degrees.

2) In the question the polynomial is of degree two which means it has 2 zeroes, and quadratic equation is denoted as:

• ax²+bx+c = 0

or

• (x+a)(x+b)=0

as per the question,

• (x+3) (x-7) = 0

which means that (x+3) = 0 or (x-7) = 0

so the zeroes are

• x = -3 or x = 7

The integral zeros of the given polynomial are -3 and 7.

Answer 2

Answer:

x= -3 , x= 7

Step-by-step explanation:

hope it help you