Question

Find it........... Perimeter....

Answer 1

Hey friend here is ur answer

plz see this attachment
hope this helps u.

Answer 2

Area of eq. triangle=20 * sqrt(3) m^2

(sqrt(3)/4) a^2=20 * sqrt(3) m^2

sqrt(3) is at both sides,thus both cancelled.

a^2=20*4 m^2

a^2=80 m^2

a=sqrt(80) m

Now,

Perimeter=a+a+a

=sqrt(80)+sqrt(80)+sqrt(80)

=26.83 (exact to the second decimal place)