Math, asked by sakshi345, 1 year ago

find it plzzzzzzzzzzzzz

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Answers

Answered by warrior0609
0
rationalise the number
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Answered by DaIncredible
0
Heya there !!!
Here is the answer you were looking for:

Identity used :

(x + y)(x - y) =  {x}^{2}  -  {y}^{2}


Given,
x = 3- 2√2

 =  \frac{1}{x}  \\  \\

Putting the value of x we get,

 \frac{1}{x}  =  \frac{1}{3 - 2 \sqrt{2} }  \\

On rationalizing the denominator we are,

 \frac{1}{x}  =  \frac{1}{3 - 2 \sqrt{2} }  \times  \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} }  \\  \\  \frac{1}{x}  =  \frac{3 + 2 \sqrt{2} }{ {(3)}^{2}  -  {(2 \sqrt{2} )}^{2} }  \\  \\  \frac{1}{x}  =  \frac{3 + 2 \sqrt{2} }{9 - 8}  \\  \\   \frac{1}{x}  = 3 + 2 \sqrt{2}

Hope this helps!!!

If you have any doubt regarding to my answer, feel free to ask me in the comment section ^_^

@Mahak24

Thanks....
☺☺

DaIncredible: thanks for brainliest ^_^
sakshi345: welcome
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