find its roots by square methord.
√2x^2+7x+5
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Answer:
root2x^2+7x+5
let it solve,
2x^2+7x=-5
x^2+7x/2=-5/2
x^2+7x/2+49/4=-5/2+49/4
(x+7/2) ^2=9/16
x+7/2=3/4
then,
x=-11/4
I hope it's helpful for you
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