Find k for which 2x+3y=0 and kx+6y=0 has a nonzero solution
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Answer:
k = 4
Step-by-step explanation:
(2x+3y = 0)2 = 4x+6y = 0 =>> 6y = -4x
kx-4x = 0
kx = 4x
k = 4
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