Question

Find k for which the quadratic equation kx(x-3)+9 = 0

Answer 1

kx^2-3kx+9=0
Simplifying kx2 + -3kx + 9 = 0
  Reorder the terms: 9 + -3kx + kx2 = 0
 Solving 9 + -3kx + kx2 = 0
 Solving for variable 'k'.
 Move all terms containing k to the left, all other terms to the right
. Add '-9' to each side of the equation. 9 + -3kx + -9 + kx2 = 0 + -9
 Reorder the terms: 9 + -9 + -3kx + kx2 = 0 + -9
 Combine like terms: 9 + -9 = 0 0 + -3kx + kx2 = 0 + -9 -3kx + kx2 = 0 + -9 Combine like terms: 0 + -9 = -9 -3kx + kx2 = -9 Reorder the terms: 9 + -3kx + kx2 = -9 + 9
 Combine like terms: -9 + 9 = 0 9 + -3kx + kx2 = 0