find K if equation has equal roots 2x²+Kx+3=0
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Solution
Given :-
- Equation, 2x² + kx + 3 = 0 ------(1)
- Roots are equal of this equation
Find :-
- Value of k
Explanation
Important Formula
★ Sum of zeroes = -b/a
★ Product of zeroes = c/a
Where,
- a = Coefficient of x²
- b = Coefficient of x
- c = Constant part
Let, P & q are zeroes of this equation,
So, A/C to question,
- p = q ---------(2)
==> Sum of zeroes = -k/2
==> p + q = -k/2
By, equ(2)
==> p . p = -k/2
==> p² = -k/2 ----------(3)
And,
==> Product of zeroes = 3/2
==> p . q = 3/2
Keep Value by equ(2)
==> p . p = 3/2
==> p² = 3/2 -----------(4)
Equate equ(3) & equ(4)
==> -k/2 = 3/2
==> -k = 3 * 2/2
==> -k = 3
==> k = -3
_______________________
Hence
- Value of k = -3
__________________
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