Question

find k,if line passing through (2,k)and(-4,2) has slope 1/2​

Answer 1

Let x1 =2,x2=-4,y1 = k, y2 = 2

Slope =

$\frac{y2 - y1 }{x2 - x1}$

$\frac{1}{2} = \frac{2 - k}{4 - 2}$

$\frac{1}{2} = \frac{2 - k}{2}$

$\frac{1 \times 2}{2} = 2 - k$

$\frac{2}{2 } = 2 - k$

$1 = 2 - k$

$k = 2 - 1$

$k = 1$

Answer 2

The value of k is 5.

Explanation:

We know that the slope of a line passing through (a,b) and (c,d) is given by :-

$\text{Slope}=\dfrac{d-b}{c-a}$

Given : The line  passing through (2,k)and(-4,2) has slope $\dfrac{1}{2}$.

Put all corresponding values in the formula , we get

$\dfrac{1}{2}=\dfrac{2-k}{-4-2}$

$\Rightarrow\ \dfrac{1}{2}=\dfrac{2-k}{-6}$

$\Rightarrow\ \dfrac{1}{2}\times-6=2-k$

$\Rightarrow\ -3=2-k$

$\Rightarrow\ k=2+3=5$

Hence, the value of k is 5.

# Learn more :

Find k if slope of the line passing through (-3,k) and ( -2 , 5 ) is 3

https://brainly.in/question/2353522