Question

i knew that the answer is 3x+3y-1=0...so..i just want process to find it​

Answer 1

Step-by-step explanation:

$\frac{x}{2} + \frac{y}{2} = \frac{1}{6}$

=

$\frac{2x + 2y}{4} = \frac{1}{6}$

$6 \times (2x + 2y) = 4$

$3 \times (2x + 2y) = 2$

$6x + 6y = 2$

$6x + 6y - 2 = 0$

$2 \times (3x + 3y - 1) = 0$

$3x + 3y - 1 = 0$

Answer 2

Step-by-step explanation:

HEY MATE.....

HERE IS STEP BY STEP SOLUTION OF YOUR QUESTION...

1. x/2+y/2=1/6
2. (x+y)/2=1/6
3. x+y=1/3 [1/6×2=1/3]
4. 3(x+y)=1
5. 3x+3y=1
6. 3x+3y-1=0

NOTE: Moving a no. from RHS to LHS or vise versa,sign with no. changes just opposite e.g.multilication sign changes into division....

HOPE THAT IT WILL HELP YOU....THANK YOU...

AND MARK MY ANSWER BRAINLIEST PLEASE ...❤❤✌✌