Math, asked by nivedita17, 1 year ago

find K if one of the root of the equation 5 x square + 6x + k= 20 is 5 times the other​

Answers

Answered by bhuvaneshwari13
0

Answer:

The value of k = 9/2 = 4.5

Step-by-step explanation:

If the roots of a quadratic equation are real and equal then

Discriminant(b^2 - 4ac) of  Quadratic equation is zero.

It is given a quadratic equation

2x2- 6x + k = 0,

the roots of  are real and equal.

Therefore Discriminant of  Quadratic equation is zero.

b^2 - 4ac =0

The coefficients of  2x2- 6x + k = 0,

a = 2

b = -6

c = k

To find the value of k

b^2 - 4ac =0

(-6)^2 - 4 x 2x k = 0

8k = 36

k = 36/8 = 9 /2 = 4.5


bhuvaneshwari13: mark as brainliest answer please
bhuvaneshwari13: please
oliviagunda: where is the 20?
Answered by malavikabala012003
2

Answer : -21

I hope it helps you

Attachments:
Similar questions