Find k, if one of the roots of x²–kx+6=0 is 3.
Answers
Answered by
4
Hey
Here is your answer,
x^2 - kx + 6 = 0
(3)^2 - 3k + 6 = 0
9 - 3k + 6 = 0
-3k = -15
K = 5
Hope it helps you!
Answered by
2
x² - kx + 6 = 0
(3)² - k × 3 + 6 = 0
9 - 3k + 6 = 0
-3k + 15 = 0
k = 5
(3)² - k × 3 + 6 = 0
9 - 3k + 6 = 0
-3k + 15 = 0
k = 5
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