Find k if point A (1,2) , B (1/2,3) and C (0,k) are collinear
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Answered by
67
x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0
1(3-k)+1/2(k-2)+0(2-k)=0
3-k+1/2k-1=0
2-1/2k=0
-1/2k=-2
1/2k=2
k=4
1(3-k)+1/2(k-2)+0(2-k)=0
3-k+1/2k-1=0
2-1/2k=0
-1/2k=-2
1/2k=2
k=4
Answered by
7
Answer:
Step-by-step explanation:
According to the question.
By ∆area formula
Eq will be 6-2k+k-2=0
K=4.
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