Question

Find k if roots of the equation (k+3)x2-2(k+2)x+k=0 are in the ratio 2:5

Answer 1

2.5.3.4.6.7.7.7.8.8.8.7..

Step-by-step explanation:

1

2

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9

0

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9

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5

Answer 2

Answer:

k = -2

Step-by-step explanation:

(k+3)x2-2(k+2)x+k = 0

2k+6-2kx-4x+k = 0

3k+6-2kx-4x = 0

-2kx-4x+3k+6 = 0

-2x(k+2)+3(k+2) = 0

(k+2) (-2x+3) = 0

k = -2

x = 3/2