Question

Find k, if system of equation has unique solution 2x + 3y = 5 and 4x +ky = 1​

Answer 1

Answer:

Given equations are 2x+3y−5=0 and 4x+ky−10=0

Then 2x+3y−5=0⇒2x+3y=5

4x+ky−10⇒4x+ky=10

∴  4 2 ​   =  k 3 =  

105  .... [Since, they have an infinite number of solutions]

⇒  2 1   =  k 3  =  

2 1⇒  2 1 =  k

3⇒k=6

Step-by-step explanation:

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