Question

Find k, if the area of the triangle whose vertices are A(4, k), B(-5, -7) and C(-4, 1) is 38 sq. units.

Answer 1

Answer:

Step-by-step explanation:

By using this formula you can solve 1/2{X1 (y2-y3)+X2 (y3-y1)+X3 (Y1-y2)}

Answer 2

A(4,k) B(-5,-7) C(-4,1)
area of triangle=1/2{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}
38=1/2{4(-7-1)-5(1-k)-4(k+7)}
38=1/2{4(-8)-5(1-k)-4(k+7)}
38=1/2{-32-5(1-k)-4(k+7)}
38=1/2{-32-5+5k-4k-28)}
38=1/2{-62+k}
38×2=-62+k
76=-62+k
76-62=k
14=k

Value of k is 14

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