Question

find k if the point are (8,1) (3,-4) (k,-5) are collinear​

Answer 1

Answer:

here, x'=8, y'=1, x"=3, y"=-4, x"'=k, y"'=-5

since points are collinear

then, area of triangle=0

x'(y"-y"') +x"(y"'-y') +x"'(y'-y") =0

8(-4+5) +3(-5-1) +k(1+4) =0

8(1) +3(-6) +k(5) =0

8-18+5k=0

-10+5k=0

5k=10

k=10/5

k=2 ans..