find k if the points are collinear (k,1) (1,-1) and (11,4)
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Answer: k=5
Step-by-step explanation:
For k to be zero:-
Area of the triangle formed by the given points=0
1/2[x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)]=0
k(-1-4)+1(4-1)+11(1+1)=0
5k=3+22
k=25/5=5(Ans)
Mark brainliest..............
Value of k= 5
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