Question

find k if the solpe of line PQ is parallel to line RS where p(2,4) q(3,6) r(8,1) and s(10,k)

Answer 1

value of k will be five

Answer 2

Answer:

k = 5

Step-by-step explanation:

In the question,

W have been provided that the line PQ is parallel to the the line RS.

So,

P (2, 4), Q (3, 6), R (8, 1) and S (10, k).

So,

As the slope of the line is given by,

$Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

So,

Slope of the line PQ is given by,

$Slope=\frac{6-4}{3-2}=2$

So, the slope of the line PQ is 2.

Now,

Slope of line RS is given by,

$Slope =\frac{k-1}{10-8}=\frac{k-1}{2}$

Now, as the parallel lines have the same slope.

Therefore,

$2=\frac{k-1}{2}\\k-1=4\\k=5$

Therefore, the value of k is given by,

k = 5.