Find K, if the sum of the zeroes of the polynomial x2 -(k+6) x + 2 (2k-1) is half their product.
Answers
Answered by
19
k+6)/1=2(2k-1)/2
k+6=2k-1
2k-k=6+1
k=7
k+6=2k-1
2k-k=6+1
k=7
amohd1791pbx61c:
sorry but your answer is wrong because according to the question The sum of zeros if half the product. You have not use half
yes..i forget.thnks
hmmm
welcom
Answered by
37
Sum of zeros is 'a' + 'B' = -b/a
product of zeros is aB = c/a
According to the question,
a + B = aB/2
-b/a = c/a/2
k + 6 = 2(2k-1)/2
k + 6 = 2k - 1
-k = -7
k = 7
product of zeros is aB = c/a
According to the question,
a + B = aB/2
-b/a = c/a/2
k + 6 = 2(2k-1)/2
k + 6 = 2k - 1
-k = -7
k = 7
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