Question

find k if the system of equation have infinite no. of solutions 2x-y-5=0 and 4x-2y+k=0​

Answer 1

Answer:

Step-by-step explanation:

Given equations are 2x+3y−5=0 and 4x+ky−10=0

Then 2x+3y−5=0⇒2x+3y=5

4x+ky−10⇒4x+ky=10

∴  

4

2

​

=  

k

3

​

=  

10

5

​

 .... [Since, they have an infinite number of solutions]

⇒  

2

1

​

=  

k

3

​

=  

2

1

​

 

⇒  

2

1

​

=  

k

3

​

 

⇒k=6