find k if x-1 is a factor of the polynomial x cube +3x square +5k +6
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Step-by-step explanation:
k=-2 ........... is the answer
x-1 is factor of polynomial so x=1 will satisfy the equation
P(1)=0
1³+3×1²+5k+6=0
archanadss2811:
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Answer:
f(x) = x^3+3x^2+5k+6 ( ^ stands for raise to the power)
g(x) = x-1
Its given in the question that g(x) is a factor of P(x)
So therefore, x-1 = 0
x = 1
Putting the value in p(x)
P(1) = 1^3 + 3 (1) ^2 + 5k + 6
Now simplifying the equation
p(1) = 1 + 3 +5k +6 = 0
p(1) = 10 + 5k = 0
p(1) = 10 = - 5k
k = -2
So therefore the value of k = -2
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