Math, asked by AAnilchanglani, 9 months ago

Find k, if x= 2 is a root of the
equation k x²+5x+6=0​

Answers

Answered by ravibharathi22
0

Answer:

k = -4

Step-by-step explanation:

Attachments:
Answered by KDPatak
0

Solution :

Given:

  • x = 2
  • P(x) =Kx^2 +5x+6 = 0

If a is a root of the polynomial P(x) then P(a) = 0

Using the same principle above we can find value of k.

P(x) = kx^2 +5x+6=0

P(2) = 4k +10 +6 = 0

or , 4k +16 = 0

or, 4k = -16

or, K = -4

Verification: by putting k = -4 in P(x).

P(x) = kx^2 +5x+6

or, P(x) = -4x^2+5x + 6

Putting Value of x = 2

P(2) = -4x4 +10 +6

or, P(2) = -16 +16

or, P(2) = 0

Hence, value of k is correct.

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