Find k, if x= 2 is a root of the
equation k x²+5x+6=0
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Answer:
k = -4
Step-by-step explanation:
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Solution :
Given:
- x = 2
- P(x) =Kx^2 +5x+6 = 0
If a is a root of the polynomial P(x) then P(a) = 0
Using the same principle above we can find value of k.
P(x) = kx^2 +5x+6=0
P(2) = 4k +10 +6 = 0
or , 4k +16 = 0
or, 4k = -16
or, K = -4
Verification: by putting k = -4 in P(x).
P(x) = kx^2 +5x+6
or, P(x) = -4x^2+5x + 6
Putting Value of x = 2
P(2) = -4x4 +10 +6
or, P(2) = -16 +16
or, P(2) = 0
Hence, value of k is correct.
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