find k if x = 3 is a root of equation kx^2-10x+3 = 0
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hay!!
Dear friend -
we know that given in question x=3
Let, put the value of x in given equation
=> kx²-10x+3=0
=> 3(k)² -(10×3) +3=0
=> 3k²-30+3=0
=> 3k²-27=0
=> 3k²=27
=> k²=27/3
=>k²=9
=> k=3
I hope it's help you
Dear friend -
we know that given in question x=3
Let, put the value of x in given equation
=> kx²-10x+3=0
=> 3(k)² -(10×3) +3=0
=> 3k²-30+3=0
=> 3k²-27=0
=> 3k²=27
=> k²=27/3
=>k²=9
=> k=3
I hope it's help you
RivenDost:
it depends upon the person who had asked the question
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