Question

find k ,if x²+xk+k=0 ,and the roots are real and equal​

Answer 1

Answer:

4

Step-by-step explanation:

Comparing x²+xk+k=0 with ax²+bx+c=0

we get

a=1

b=k

c=k

Discriminant =b²-4ac

but; the roots are real and equal

therefore,

b²-4ac=0

k²-4×1×k =0

k²-4k=0

k²=4k

k²/k= 4

k=4

Please mark me as Brainliest

and follow me if you find this answer helpful and wish to receive such practical and understandable answers.